What is the probability that a poker hand of 5 cards contain exactly 1 ace?
Let A be the event that a poker hand of 5 cards contain exactly 1 ace.
P (A) = (4 C 1)*(48 C 4) / (52 C 5) = .2995
What is the probability that a poker hand of 5 cards contain exactly 1 ace?
![What is the probability that a poker hand of 5 cards contain exactly 1 ace?]()
Reviewed by MCH
on
July 22, 2012
Rating:
No comments: